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## Homework Statement

Find y as a function of t if 36y''-132y'+121y=0, y(0)=5, y'(0)=4

## The Attempt at a Solution

36y''-132y'+121y=0

36r^2-132r+121=0

(6r-11)^2

So, general solution

y(x) = C1*e^(11x/6)+C2*x*e^(11x/6)

y'(x)=(11/6)*C1*e^(11x/6)+C2*e^(11x/6)*((6x-11)-(36/121))

y(0)= C1=5

y'(0)= (11/6)*5+(-36/121)*C2=4

(-36/121)*C2=(-31/6)

C2=(3751/216)

So,

y(x)=5e^((11/6)t)+(3751/216)t*e^((11/6)t)

This is for an online homework and it's wrong, but I can't figure out where I went wrong. Can someone help me out?